Question

Need help.

What is X/X^2-1 subtract 2/X+1

Answer 1

start by factorising the denominator of the 1st fraction its the difference of 2 squares.

\[\frac{x}{(x -1)(x + 1)} - \frac{2}{x + 1}\]

you will need a common denominator so that you can subtract the fractions

so the 2nd fraction needs to be multiplied by (x-1)/(x -1)


\[\frac{x}{(x -1)(x +1)} - \frac{2}{(x +1)} \times \frac{(x -1)}{(x - 1)}\]

this will result in

\[\frac{x}{(x -1)(x+1)} - \frac{2(x -1)}{(x -1)(x +1)}\]

since the denominators are the same, just work on simplifying the numerators.