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Mathematics 15 Online
OpenStudy (anonymous):

simplify: log 5 (5)

OpenStudy (anonymous):

\[\log _{5} (5)\]

OpenStudy (anonymous):

\[\log_{5} 5^{1}=1\] The log base n of n raised to a power is just what ever the power is.

jimthompson5910 (jim_thompson5910):

In general \[\Large \log_{b} (b) = 1\] where b is some positive number that is not equal to 1

OpenStudy (anonymous):

what if i have \[2\log _{2} (7)\]

jimthompson5910 (jim_thompson5910):

There's not much you can do other than use a calculator to approximate that

OpenStudy (anonymous):

how?

jimthompson5910 (jim_thompson5910):

\[\Large 2\log _{2} (7) = 2*\log(7)/\log(2)\]

jimthompson5910 (jim_thompson5910):

so you would type in 2*log(7)/log(2)

OpenStudy (anonymous):

i got 5.6 or 6

jimthompson5910 (jim_thompson5910):

\[\Large 2\log _{2} (7) \approx 5.6147098441152\] and when you round it to one decimal place you get 5.6 so you're correct

OpenStudy (anonymous):

but the correct answer here is 7.

jimthompson5910 (jim_thompson5910):

something must be missing then

jimthompson5910 (jim_thompson5910):

typo maybe?

OpenStudy (anonymous):

\[2^{\log}_{2} ^ (7)\]

OpenStudy (anonymous):

Change of base \[\log_{2} 49=\frac{ \ln 49 }{ \ln 2}\]

OpenStudy (anonymous):

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