An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's final gravitational potential energy relative to her original position?

784 J
3.9 × 10^3 J
2.7 × 10^4 J-This is the answer I got, but I am not sure if I am right?
3.1 × 10^5 J

Question

An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's final gravitational potential energy relative to her original position? 

784 J 
3.9 × 10^3 J 
2.7 × 10^4 J-This is the answer I got, but I am not sure if I am right? 
3.1 × 10^5 J

anonymous · Answer

Sin(5) = h/400

h = 400Sin(5) = 34.8622971

Potential Energy = mgh = mass*gravitational acceleration*height

$$PE = (80kg)(9.81m/s^{2})(34.8622971)$$
$$= 27,359.93 \frac{ m^2kg }{ s^2 } = 2.7 \times 10^4 J$$

So yes, you are right...