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how do I find y' derivative for this y=(x + (1/x)) (x-(1/x)) ?
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ok f'(x) = y f'(x) = (x+ ( 1 / x)) ( x - (1 / x ) first use the predicate rule f'(x) = (x + ( 1 / x )) ( 1- ( 1/ x^2) ) + ( 1 + 1 / x^2 ) ( x - (1/x )) if you do not need to simply the answer above is perfect.
Thanks! Still kinda confusing but gonna analyze it more.
well he the product rule is used when you have two things to multiply so if you have x * y for insistence to take the derivative of it you you do this dx * y + x * dy so if you look again i did this hits the derivative of 1/x is 1/x^2 x is 1
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