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This reaction is highly exothermic, releasing 848 kJ of energy. Rewrite this equation as a thermochemical equation
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\[2Al(s) + Fe _{2}O _{3}(s) \rightarrow 2 Fe(l) + Al _{2}O _{3}(s)\]
if energy is released, it must be expressed as a product
?
put the energy into the reaction as a product
I'd do this how?
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write "+ energy" on the right side of the equation
\[2Al(s)+Fe2O3(s)→2Fe(l)+Al2O3(s)\] + 848 kJ?
sure, or you can simply write energy and write at the end: \[\Delta H= - 848 kJ\]
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