Question

What is the equation of the line that passes through the points (−2, 1) and (1, 10)?

Answer 1

In point slope, the equation is\[(y-1) = 3(x+2)\]

Answer 2

Right I understand how do you do it though

Answer 3

IMPORTANT LINE RELATED EQUATIONS TO KNOW AND MEMORIZE

slope formula
m= slope/ gradiant -- same thing
\[m=\frac{y_2-y_1}{x_2-x_1}\]

standard formula
\[Ax+By=C\]

point-slope formula
\[y-y_1=m(x-x_1)\]

slope-intercept formula
b= y-intercept -- in the form of (0,y)

\[y=mx+b\]

Answer 4

first you start off by determining the slope of the line

then you can put it in point slope form and convert it into slope intercept form
or standard form depending on what hte question is asking for

personally i usually write line equations in slope intercept form as the final form

Answer 5

ok but how do you determine the slope

Answer 6

The general formula for finding slope (m) is in his post, but here it is anyway:

\[\frac{ y_2 - y_1 }{ x_2 - x_1 }\]

Or, as I like to say, rise over run (but that's kinda confusing and elementary)

Answer 7

ok so the slope would be 3/9 or 1/3

Answer 8

The slope would be 3.

\[\frac{ 10-1 }{ 1+2 } = \frac{ 9 }{ 3 } = 3\]

Answer 9

right i flipped it

Answer 10

Can anybody help me

Answer 11

A solution calculated with Mathematica 9 is attached.

Answer 12

Thanks so muck robotobey