From a boat on the lake, the angle of elevation to the top of a cliff is 11°50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)?

Question

anonymous · Answer

help help!

anonymous · Answer

$$Tan(11+\frac{ 5 }{ 6 })=\frac{ x }{ 1568}$$
Can you solve from here?

anonymous · Answer

@evansda ummm im not sure.. can you explain little further?

mathteacher1729 · Answer

Did you draw a picture? Understanding the "angle of elevation" is crucial.

anonymous · Answer

|dw:1361630244105:dw|

then use the following
$$\Large \frac{h}{1568}=\tan(11.08)$$