Question

From a boat on the lake, the angle of elevation to the top of a cliff is 11°50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)?

Answer 1

help help!

Answer 2

\[Tan(11+\frac{ 5 }{ 6 })=\frac{ x }{ 1568}\]
Can you solve from here?

Answer 3

@evansda ummm im not sure.. can you explain little further?

Answer 4

Did you draw a picture? Understanding the "angle of elevation" is crucial.

Answer 5

then use the following
\[\Large \frac{h}{1568}=\tan(11.08)\]