Question

PLEASE HELP, URGENT.
Write an equation of a line passing through (-5, 9) and is perpendicular to 2x+3y=4.

Answer 1

since the line is perpendicular so the product of the slopes of the two lines will be -1
slope of the given line is
m=-2/3
slope of requirede line must be
\[\Large slope=\frac{-1}{m}=\frac{-1}{\frac{-2}{3}}=\frac{3}{2}\]
now use point slope form
y-y0=m(x-x0)
where
m=3/2
x0=-5
yo=9
put these values in the above equation to get the equation of line

Answer 2

umm.... I'm not sure what this is supposed to mean:
\[\Large slope=\frac{-1}{m}=\frac{-1}{\frac{-2}{3}}=\frac{3}{2}\]

Answer 3

since it is given that lines are perpendicular
for the perpendicular lines with slopes m1 and m2 following must be satisfied .
\[\Large m_{1}m_{2}=-1\]

it means if the lines are perpendicular and you know the slope of one line line the slope of the other line will be the -1 of the reciprocal of the perdicular line to it
\[\Large m_{2}=\frac{-1}{m_{1}}\]

since we already know the slope of one line
\[\Large m_{1}=\frac{-2}{3}\]

so slope of the line perpendicular to it can be found easily .
\[\Large m_{2}=\frac{-1}{m_{1}}=\frac{-1}{\frac{-2}{3}}=\frac{3}{2}\]
this is slope of the required line .

Answer 4

let me know if don't follow this.

Answer 5

OH NVM, the equations just weren't loading, OKAY, I got it now!

Answer 6

THANK YOU!