Integral Trig Substitutions.
Where do the equations that are given to use the certain trig function in certain cases
if you have a proof , that's what im looking for
bascally you can test them after but i'm wondering how'd you do it with a triangle before guessing
I'm not sure what you mean, but see if the picture below helps you.
not quite i understand this it's where they get these rules
@.Sam.
in other words how'd they know to use sec,sin,and tan...
It depends on the question, if its \[a^2-x^2\] Then from triangle |dw:1361605801008:dw| You know that \[\sin(\theta)=\frac{x}{a} \\ \\ x=asin(\theta)\]
whered you get the triangle
basically i'm asking how do they get the triangle, is it simply guess and check or is there a way that if i don't remember these rules that i can use trig to find these
Its from \[a^2-x^2\] Another example, if its \[a^2+x^2\] Notice the plus is given for adjacent side and opposite side, Pythagoras theorem. |dw:1361606125590:dw| then you get \[x=atan(\theta)\]
I mean why do derivatives of certain cartesian functions yield a trig function
You need it only if you have something like this, you can use trig substitution for 1/sqrt(a^2+x^2). But that depends on the overall equation.
where does this come into play... for example you have the inverse of tan(x) yields a derivative of 1/x^2+1
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