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Chemistry 16 Online
OpenStudy (frostbite):

What molecule do you get from the following 1H-NMR/IR diagram?

OpenStudy (frostbite):

@blues @aaronq

OpenStudy (frostbite):

Would be good if it was explained, as I need to master this very soon.

OpenStudy (abb0t):

its hard for undergrads 2 master NMR. idk many who really "master" it at that lvl. but based on numbers given, 2260 if i rmr is an alkyne. asymmetric alkyne. ~1750 is C=O bond, but varies with groups. for the H-NMR The area under the NMR resonance is proportional to the number of hydrogens which that resonance represents. Do you know integration?

OpenStudy (frostbite):

I would have that the 2266 should be a nitrile group. Integration as in math or integration as in NMR? :P

OpenStudy (abb0t):

Lol. NMR.

OpenStudy (frostbite):

But yes I do :)

OpenStudy (frostbite):

The integration tells us the relative number of protons that give rise to each signal

OpenStudy (abb0t):

yes. u can get an approximation of the ratoi of hdrongesn

OpenStudy (abb0t):

w/ the given formula, u can get an idea. that's how i would raltionalize it.

OpenStudy (frostbite):

But becuase the approximation fits the number of protons we know there are then we just have to get the protons placed right. And I simple can't placed that nitrogen and one oxygen right.

OpenStudy (abb0t):

That's how I did it. I was usually right. Lol. H-NMR was by far the toughest for me.

OpenStudy (abb0t):

H-NMR, then C-NMR, and IR was easier of the three.

OpenStudy (frostbite):

But what molecule would you get if you had to analyze this one?

OpenStudy (frostbite):

I can't get all the functional groups placed with only 5 carbon.

OpenStudy (aaronq):

couldn't really fit the carbonyl and the triple bond either.. and tried it without the alkyne n i couldn't fit the carbonyl with that few hydrogens.. so disregarding the IR i came up with this: |dw:1361655219961:dw| 2 hydrogens being split by 3, quartet 3 hydrogens being split by 2, triplet 2 not split

OpenStudy (frostbite):

What about this one? |dw:1361783312905:dw|

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