Question

c(x)=250+6x+0.1x^2
marginal average cost at a production level of 30 units.

Answer 1

i believe its the derivative of cost at 30 unites

Answer 2

0+6+0.2x?

Answer 3

very good, now when x=30, thats what .... 6 + 6 = 12 ?

Answer 4

6+0.2(30) =12

Answer 5

great! :)

Answer 6

but the answer here is -0.18

Answer 7

make sure your information that you posted is accurate

Answer 8

it is.

Answer 9

hmmm, then i missed something while reading.

We are given the cost function C(x)

the average cost function is therefore C(x)/x ... thats where i missed it

the marginal average cost function is the derivative of C(x)/x .... not C(x)

Answer 10

marginal cost at a pro lev. of 30 units.. =12
average cost func. is=250/x +6+0.1x
marginal cost function is -250/x^2+0.1 ... i understand that part. except that marginal average cost

Answer 11

im reviewing for my test. ;) hehe

Answer 12

\[\frac{c(x)=250+6x+0.1x^2}{x}\]\[\frac{c(x)}{x}=250x^{-1}+6+0.1x\]
\[D_x[\frac{c(x)}{x}]=-250x^{-2}+0+0.1\]
\[-\frac{250}{30.30}+0.1\]
\[-\frac{2.5}{9}+0.1\]
\[-.27777....+0.1\]
\[-.17777....\]

Answer 13

the word marginal always brings to mind a derivative of what is being marginalized

marginal (average cost) is the derivative of (average cost)

Answer 14

how did u get 2.5/9? o.o

Answer 15

ah nvm . i get it hehe

Answer 16

ahhh!! ;)

Answer 17

i got .377777777

Answer 18

but if i subtract 0.1. i get .17777777778

Answer 19

again. nvm. i just forgot to put - sign haha. thanks soo much! ;)