Question

let v1=(2,-6) and v2= (-4,7)
(a) compute |v1| and |v2|

Answer 1

x1=2
y1=-6

\[ |v1|=\sqrt{x1^2+y1^2}\]

Answer 2

can u solved v1 now?

Answer 3

yes i got sqrt -36

Answer 4

*32

Answer 5

wrong

Answer 6

what did I do wrong then?

Answer 7

sqrt of 40

Answer 8

\[|v1|=\sqrt{(2)^2+(-6)^2}\]

Answer 9

correct

Answer 10

can u solved v2 now?

Answer 11

i got sqrt of 40 I messed up with the negative sign

Answer 12

how would i find |v2| ?

Answer 13

x1=-4
y1=7

Answer 14

can u solved v2 now?

Answer 15

sqrt of 65. How would I also do v1+v2? would i justadd 2-4 and multiply it by -6+7?

Answer 16

v1+v2=2x1-6y1-4x1+7y1=-2x1+y1=(-2,1)