6r^4+11r^2=0

Question

6r^4+11r^2=0

anonymous · Answer

does the equations look like this on your paper? 

(6r)^4 + (11r)^2 = 0

anonymous · Answer

No parenthesis in the equation...

anonymous · Answer

That means you would only put the r to the 4th power and square the second r. 

is 15r^6 an answer?

anonymous · Answer

The answer is -10/2i, 10/2i   -6/3, 6/3. Radical sign before the ten and six....it's a quadratic equation...tryin to find out a easy process

anonymous · Answer

Square root sign I meant

anonymous · Answer

$$6r^4+11r^2=0\
r^2(6r^2+11)=0$$
$$r^2=0\text{ and }6r^2+11=0$$
The first equation tells you that r = 0 is a solution.
Solving for r in the second equation gives you
$$r=\pm \;i\sqrt{\frac{11}{6}}$$
Are you sure that's the right equation?

anonymous · Answer

That's how it's writen in the book...

anonymous · Answer

http://www.wolframalpha.com/input/?i=6r%5E4%2B11r%5E2%3D0