Question

find the derivative of y= r/(r^(2)+8)^1/2 using chain rule

Answer 1

You will come across the chain rule while doing the quotient rule/product rule so start with that.

Answer 2

I got r*-1/2*(2r)^(-3/2)+1*(r^(2)+8)^-1/2 doing product rule

Answer 3

The chain rule wasn't applied correctly
When differentiating (r^2+8)^(-1/2) you get -1/2(r^2+8)^(-3/2)*(2r)
You differentiate the composition: f(g(x)) as f'(g(x))g'(x). So see the -1/2(...)^(-3/2) still has my g(x) inside., not g'(x)

Answer 4

Ohh that makes sense. then what do you do with the numerator?