Question

What is the simplified form of (1/y)-(1/x) / (1/y) +(1/y)? :))

Answer 1

\[\frac{ \frac{ 1 }{y } -\frac{ 1 }{ x } }{ \frac{ 1 }{ y } +\frac{ 1 }{ y } }\]

\[\frac{ \frac{ 1 }{ y } - \frac{ 1 }{ x}}{ \frac{ 2 }{ y } }\]

then keep, change, ad flip (multiply reciprocal of second fraction

\[\left( \frac{ 1x }{ xy } - \frac{ 1y }{xy }\right) \frac{ y }{2 }\]

\[\left( \frac{ x-y }{ xy } \right) \frac{ y }{ 2}\]

\[\frac{ y \left( x-1 \right) }{ 2xy }\]

= \[\frac{ xy-y }{ 2xy }\]

Answer 2

dam, although the answer is correct, im giving a medal for the Latex

Answer 3

The answer isn't correct though.

Answer 4

A \(y\) became a \(1\) for some reason.

Answer 5

\[
\left( \frac{ x-y }{ xy } \right) \frac{ y }{ 2}\neq \frac{y(x-1)}{2xy}
\]\[
\left( \frac{ x-y }{ xy } \right) \frac{ y }{ 2}=\frac{y(x-y)}{2xy}
\]

Answer 6

Oh, where did your smart remark go?

Answer 7

@wio thats not an option :/

Answer 8

You typed the question incorrectly.

Answer 9

\[\frac{ xy - y ^{2} }{ 2xy }\]

it was my mistake

Answer 10

\[ \Large
\begin{split}

\frac{\frac{1}{y}-\frac{1}{x}}{\frac{1}{y}+\frac{1}{x}}
&= \frac{\frac{y-x}{yx}}{\frac{y+x}{xy}} \\
&= \frac{y-x}{y+x}

\end{split}
\]