Question

What is the general form of an equation that represents the line that passes through the points ( -9, -5) and (3, 8) ?
A) 12x-13y-57=0
B) 13x+12y-57=0
C) 13x-12y+57=0
D) 12x+13y+57=0

Answer 1

first find the slope of the line.

\[slope = m=\frac{y2-y1}{x2-x1}=\frac{8-(-5)}{3-(-9)}=\frac{13}{12}\]
\[y = mx+b\]
plug in one of the order pairs into the above equation to find b. then just move everything to the left side of the = sign.

Answer 2

Eh I dont get it..

Answer 3

https://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/slope-and-intercepts/v/algebra--slope-3

Answer 4

It only shows me how to find the slope not the whole equation.

Answer 5

use the formula :
(y - y1)/(y2-y1) = (x - x1)/(x2 - x1)

Answer 6

\[(y-y_1)=m(x-x_1)\]
then use algebra to rearrange it to standard form: y = mx+b