Question

can somebody help me with th slope of each line and then detemine whether th two lines are parrelel, perpendicular, or neither -5x+3y=3 and 2x+7y=0

Answer 1

neither

Answer 2

To get the slope, rearrange the equation in slope intercept form: \(y = mx+b\) where \(m\) is the slope.

Parallel lines have = slope.
Perpendicular lines have slopes such that the product = -1

Answer 3

but what would be the slopes i came up with 1/3 and 2x/7 did imiss somethn

Answer 4

\[-5x+3y=3\]add 5x to both sides\[3y=5x+3\]divide by 3\[y=\frac{5}{3}x+1\]\[m=\frac{5}3\]
\[2x+7y=0\]subtract 2x from both sides\[7y=-2x\]divide by 7\[y=-\frac{2}{7}x\]\[m=-\frac{2}{7}\]

Answer 5

the slopes aren't equal, and their product does not equal -1, so they are neither parallel nor perpendicular.

Answer 6

thats whats up thank u ima be back to ask you a ? lol

Answer 7

were can i get grah help from

Answer 8

My magic decoder ring suggests that you meant to ask:
"Where can I get help with graphs?"

If that is true, could you be a bit more specific? Do you need help reading them, making them, or what?

Answer 9

i got a problem write the qation for the line the points on here is at the(x 2 y 5)nd 0,6the equation of the line is y= type y+x+b

Answer 10

How about you try writing that again?

Answer 11

point 2,5 and 0,6 write the equation for the line use y=mx+b

Answer 12

Okay, the equation for the slope given two points \((x_1,y_1),(x_2,y_2)\) is \[m=\frac{y_2-y_1}{x_2-x_1}\]

Once you have the slope, the equation for a line with known slope \(m\) going through a point \((x_0,y_0)\) is \[y-y_0=m(x-x_0)\]
and then a bit of algebra to rearrange it into the requested slope-intercept form.

Answer 13

the slope would be 1/-3 rise over run up one to the left 3

Answer 14

1/-2 my bad

Answer 15

Okay, your latter value for the slope is correct.

Answer 16

how would i make the problem 6-5=1 and 0-2=2 h ld i turn this into y= answer

Answer 17

how would i turn this into an equation solving y=

Answer 18

You know the slope, and you know a point on the line. Use the second formula in my post to construct the equation.

Answer 19

correct me im wrong here y=6-5=1/2(0-2)

Answer 20

You only use 1 point, not 2.

Answer 21

oh so y=6x-5

Answer 22

im not getting how you come up with the solution for what i have figued out

Answer 23

Okay, you got the slope, m = -1/2, right?

Now use the formula for a line given the slope and a known point:
\[y-y_0 = m(x-x_0)\]Our known point is (2,5):
\[y-5=-\frac{1}{2}(x-2)\]You could also do it with the other known point (0,6):
\[y-6=-\frac{1}{2}(x-0)\]Now add 5 or 6 respectively to both sides and simplify.

Answer 24

final answer y=-1/2+4

Answer 25

y-5=2-xover 2

Answer 26

No...your first answer has no \(x\) in it. Your second answer isn't in the proper form.

\[y-5=-\frac{1}{2}(x-2)\]Add 5 to both sides. Now use the distributive property to expand the right hand side and simplify. Don't forget that -ive * -ive = +ive.