Question

P(1,1) & Q(3,2) are 2 points & R is a any point on x-axis such that PQ +QR = minimum.
R=?

Answer 1

WTF :/

Answer 2

So, you learnt calculus? maxima minima, differentiating etc?

Answer 3

yes

Answer 4

1st derivative=maxima
2nd=minima :)

Answer 5

wow! :O

Answer 6

NO

Answer 7

oh sorry :P
2nd derivative is negative or smt

Answer 8

isnt it :o

Answer 9

lets go step by step.

Answer 10

k

Answer 11

take a point R(x,0)

Answer 12

RP + RQ = s

we have to minimize s.
Right?

Answer 13

yes

Answer 14

elaborate that eqn,

Answer 15

\[RP=\sqrt{1+(1-x)^2}\]

Answer 16

wow! :O

Answer 17

NO

Answer 18

lol why :/

Answer 19

re-check RQ

Answer 20

\[\LARGE S=\sqrt{1+(1-x)^2} + \sqrt{4+(x-3)^2}\]

Answer 21

yep. But it'll be a lengthy differentiation, are you up for it ? B|

Answer 22

i have a one step solution answer tbh

Answer 23

hmm, leme re-think.

Answer 24

sure,ill hint in the end if you fail

Answer 25

5/3 ?

Answer 26

woah ! :O

Answer 27

B|

Answer 28

arre :P ?

Answer 29

pehle apna solution batao, mera soln thora ajeeb hai! :|