Find the equation of the tangent line x^4 + xy + y^4 3 at (1,1)
rewrite the equation clearly please.
\[x ^{4}+xy+y ^{4}=3 \] at (1,1)
the answer is f(x)=-1
Can you elaborate more on the steps you took if you don't mind?
Ok give me 5 min. i will explain. Do you know what does derivative mean? in geometric view?
I know \[y-y _{1}=m(x-x _{1})\] is used right? I have a problem finding the slope.
wait i think i made a mistake. -1 is just the slope.
can you solve other part of the problem if i explain how i found the slope?
there i attached it. take a look
now that you know the slope you can use the formula you wrote below. :)
anything wrong?
y-1=(-1)(x-1)=>y-1=1-x => y=2-x thats what ur looking for i guess.
Just comparing it to what I have.
so after you get 5yprime + 5 = 0. how does yprime then become -1?
5 y '+5=0 => 5y'=-5 => divide both side by 5 and you will get y'=-1
Gotcha :)
very good :)
Ok man, I figured it out now. Thanks a lot!!!
Your welcome. :)
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