Question

a population of bacteria is growing acording to the equation p(t)=1200e^0.17t, with t measured in years. estimate when the population will exceed 3443

Answer 1

\[3343\leq 1200e^{.07t}\]
\[\frac{3343}{1200}\leq e^{.17t}\]
\[\ln(\frac{3343}{1200})\leq .17t\]
\[\frac{\ln(\frac{3343}{1200})}{.17}\leq t\]

Answer 2

what would be the final answer