Question

What's the derivative of (1-2xe^x)/x

Answer 1

(1-2xe^x)/x = (1-2xe^x)(x^-1) use the product rule

Answer 2

I have to distribute the x^-1 first right? or can I just take the derivative of them now? How would i take the derivative of 2xe^x?

Answer 3

no don't distribute.
il show you an example:

d/dx (xe^x)

Using product rule

d/dx (uv) = u'v + uv'

u = x
u' = 1

v = e^x
v' = e^x

d/dx (xe^x) = e^x + xe^x
= e^x(1+x)

Answer 4

I'm lost... In class we never went over a product rule so

Is it possible to solve via (1/x)-[(2xe^x)/x] and then cancel x to get

1/x - (2e^x)

using the power rule and knowing that the derivative of e^x is e^x

I could conclude that the derivative would be

[-1/(x^2)]-2e^x?