Question

Derive: f(x)=x*(e^2x)*ln(x^2)... I'm thinking it is f'(x)=(e^2x)/x^2

Is this correct?

Answer 1

probably easiest to start with
\[2xe^{2x}\ln(x)\] and then you need the product rule three times

Answer 2

\[(fgh)'=f'gh+fg'h+fgh'\]

Answer 3

oh! that's simple! i just looked at it and was like what? Thanks!