plaese help me!
a physical education teacher was getting ready for gym class one day. he measured the circumference of the basketball to be 9 inches when its filled with air. he then went on to pose the following questions to his classes:
A) how much material is needed to make four basketball? (3.14 for pie)
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OpenStudy (anonymous):
b) how much air will the four balls hold combined? ( 3.14 for pie)
OpenStudy (anonymous):
c) if the basketballs are stored four to a box in cubic boxes whose edges are 15 incges long, what percent of the box is not filled by balls?
jimthompson5910 (jim_thompson5910):
part a), you're finding the surface area of the ball or sphere
jimthompson5910 (jim_thompson5910):
do you know the formula for the surface area of a sphere?
OpenStudy (anonymous):
yes
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jimthompson5910 (jim_thompson5910):
ok what is it
jimthompson5910 (jim_thompson5910):
well first off, you'll need to find the radius before you can find the surface area
OpenStudy (anonymous):
4(3.14)r squared
jimthompson5910 (jim_thompson5910):
C = 2*pi*r
9 = 2*3.14*r
solve for r
jimthompson5910 (jim_thompson5910):
good, keep that formula in mind for later
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OpenStudy (anonymous):
okay the problem u just out up is for A right?
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
r=4.5
jimthompson5910 (jim_thompson5910):
9 = 2*3.14*r
9/(2*3.14) = r
1.43312 = r
r = 1.43312
jimthompson5910 (jim_thompson5910):
now you use this in
4(3.14)r squared
to find the surface area
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OpenStudy (anonymous):
i got 25.796 for surface area
jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
that was for B right??
jimthompson5910 (jim_thompson5910):
now multiply that answer by 4
why? because that answer of 25.796 is the surface area of one basketball
but you want to make 4 basketballs
jimthompson5910 (jim_thompson5910):
no all still on part a
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OpenStudy (anonymous):
103.184
jimthompson5910 (jim_thompson5910):
that's your final answer to part a
jimthompson5910 (jim_thompson5910):
that's how much material you need to make the four basketballs
OpenStudy (anonymous):
yes i got that
OpenStudy (anonymous):
for part B do i use Volume?
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jimthompson5910 (jim_thompson5910):
yes you use the formula
V = (4/3)*pi*r^3
jimthompson5910 (jim_thompson5910):
that's to get the volume of one ball
OpenStudy (anonymous):
i got 49.2916 for 4 balls
jimthompson5910 (jim_thompson5910):
very good
jimthompson5910 (jim_thompson5910):
getting the same pretty much
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jimthompson5910 (jim_thompson5910):
so the volume of 4 balls is roughly 49.2916 cubic inches
OpenStudy (anonymous):
yes :) i don't get what i have to do for part C??
jimthompson5910 (jim_thompson5910):
what is the volume of the box?
OpenStudy (anonymous):
i don't know
jimthompson5910 (jim_thompson5910):
V = s^3
V = 15^3
V = 3375 cubic inches
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OpenStudy (anonymous):
okay i got it :)
i have one last question :)
jimthompson5910 (jim_thompson5910):
well we're not done with C, do you see how to get the answer for C?
jimthompson5910 (jim_thompson5910):
using what I gave you
OpenStudy (anonymous):
what do i do next ??
jimthompson5910 (jim_thompson5910):
the volume of the four balls was 49.2916
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jimthompson5910 (jim_thompson5910):
the volume of the box is 3375
jimthompson5910 (jim_thompson5910):
so the volume inside the box that is NOT taken up by the 4 balls is
3375 - 49.2916 = 3325.7084
jimthompson5910 (jim_thompson5910):
therefore, the percent of the box NOT filled by the balls is
3325.7084/3375 = 0.985395 = 98.5395%
jimthompson5910 (jim_thompson5910):
so you have a lot of room in this box
OpenStudy (anonymous):
got it :)
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OpenStudy (anonymous):
the school would like to sane money ans storage space by buying smaller boxes to store the balls. what is the smallest size for the box where it will still hold four balls and each edge will be a whole number/
OpenStudy (anonymous):
last question :)
jimthompson5910 (jim_thompson5910):
ok say the box had side lengths of 1 inch
this would give it a volume of 1^3 = 1 cubic inches
that's too small since we need something that will hold 49.2916 cubic inches
jimthompson5910 (jim_thompson5910):
2^3 = 8 ... still too small
3^3 = 27 ... again too small
4^3 = 64 ... not too small
jimthompson5910 (jim_thompson5910):
so the smallest box has side lengths of 4 inches
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