Question

How would you integrate this? (I'll type the integral into the comments

Answer 1

\[\int\limits_{}^{}\sqrt{secx}\tan^3xdx\]

Answer 2

\[\int\sqrt{\sec x}\tan^3x\;dx\cdot\frac{\sqrt{\sec x}}{\sqrt{\sec x}}\\
\int\frac{\sec x\tan^3x}{\sqrt{\sec x}}dx\\
\int\frac{\sec x\tan x\tan^2x}{\sqrt{\sec x}}dx\\
\int\frac{\sec x\tan x(\sec^2x-1)}{\sqrt{\sec x}}dx\]
\[u=\sec x\\
du=\sec x\tan x\;dx\]
\[\int\frac{u^2-1}{\sqrt{u}}du\]

Answer 3

Thank you very much!

Answer 4

well done, @SithsAndGiggles

Answer 5

Thanks!

Answer 6

nice :)