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find the geometric mean of 45,_,_,20 with solution please
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let r be the common ratio
the next term is obtained by mutiplying the previous term by r, in this case, what follows 45 is 45r.
the previous term is equal to the next term divided r. therefore the term before 20 is 20/r
the geometric mean is \[\large \sqrt[4]{45\cdot 45r \cdot \frac{20}{r}\cdot 20}=\sqrt[4]{45^2\cdot 20^2}=30\]
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