how do I get 3sqrt(8)+3sqrt(8)=32^(5/2) ?

Question

anonymous · Answer

$$3\sqrt{8}+3\sqrt{8}=32^{\frac{ 5 }{ 2 }}$$

terenzreignz · Answer

At face-value, this doesn't seem to be true...
$$\large 2 < \sqrt{8} < 3$$$$\large 6 < 3\sqrt{8} < 9$$

anonymous · Answer

it comes from $$3\sqrt{ 9t2−7t+8 }+3\sqrt{8t^2+6t+8 }$$ when t=0

terenzreignz · Answer

But that above is not an equation.  Do you mean that expression above is always equal to 
$$\huge 32^{\frac52}$$?

anonymous · Answer

sorry I mean $$3\sqrt{9t2−7t+8}+3\sqrt{8t2+6t+8}=32 ^{\frac{ 5 }{ 2 }}$$ when t=0

terenzreignz · Answer

Well, then, this does indeed, lead to your original equation, but I still don't see any truth in it :D
If this equation is to be true, it must be for some other t...

anonymous · Answer

ok so it must be a mistake in the solutions. I think it should say 3*2^(5/2).

so.. sqrt{8}=2*sqrt{2}=2^(3/2)
and 2*2*sqrt{2}=2^(5/2) great

terenzreignz · Answer

Oh, so that was it...