two seperate monochromatic light beams A and B of the same intensity are falling normally on a unit area of a metallic surface. their wavelengths are λa and λb respectively. assuming that all incident light is used in ejecting the photoelectrons,the ratio of the number of photoelectrons from the beam A to that from B is?
@Mashy @shubhamsrg
Number of photo electrons depends on what? (what property of the incident light?)
intensity.
good.. now read the first line of your question carefully :D
i get your point. but the answer is λa/ λb
what? :O.. thats preposterous ! wavelength only decides the kinetic energy of the electrons and not the number! :-/
that is so stupid.. and if lambda a is above the threshold wavelength, there ain't gonna be no photoelectrons :P..
that answer is 100 percent wrong!
either that or i don't have a 100 percent understanding in photoelectric effect :P
well this is a question from roorkee 1990, so i dont think it can be wrong. just think about it and tell me if you get it.
they could have given the answer wrong in your book.. the question is def right.. and the answer should be 1:1.. but lemme think mor!
1:1 is not in the options.
Ok.. the number of electrons = the no of photons Since the intensity is same, energy per second is same.. so use E = nhf .. for each one.. n = no of photons!
what?? that should give you the answer!
hmm. but you did this just to get the answer? if 1:1 was an option, it would be your first choice?
yea and that's wrong. i understand how you see.. photoelectron's directly proportional to intensity.. thats true.. it only says if you double the intensity , photoelectrons double.. only reason is because photon no.s double. . however.. it need not necessarily mean that two light source of different intensities should have same no. of photons.. and hence give same photo electrons :D.. thanks! i learnt something :D
haha. i had to read it a few of times before i could get it. thank you! :)
yea.. m very lazy to type properly these days :D.. ok i gotta go for lunch now bye!
i wish you could take my exams. :P
bye.
final ans is lambda(a)/lambda(b) right ?
yup
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