Find the domain and range of the following functions:
y=secx
Please explain :/
everywhere except where the \(\cos(x)=0\)
Can i get more explanation :/
y = sec x = 1/ cosx so all values of x are acceptable except those for which cosx = 0 so now can you sovle for those values of x?
It would be infinity na?
why cannot it be 0 then?
whoops sorry. range: [1, infinity)
1/0 is not defined who said it`s infinity
1/0=complex infinity
well let me tell you those are just ways of convincing and infinity as such has no significance infinity is no fixed point it`s better if we talk of thing like "it tends to infinity" so for all those values of x for which function is not defined are excluded from domain
Okay i got the idea so what would be the range?
And domain? @harsimran_hs4
for domain you can take out all odd multiples of pi/2 domain = {all real} - { x = n(pi/2)} where n is an integer range = {all real} - (-1, 1)
This is not helping :/ Actually i need it right from the basics :/ Please :(
i think domain might be clear?
No :(
tell me general solution of equation cosx = 0
Ok so Cosx=0 x=Cos^-1(0) x=90 degrees or pi/2
well i had asked for general solution not particular so if i say all odd multiples of pi/2 satisfy this equation do you agree?
I am not getting the point of odd multiples and what do you mean by general solution :/
x = pi/2 , 3pi/2 , 5pi/2 and so on will also satisfy this equation agreed?
Sorry,I am not that good :/,How do you know that?
by inspection or it`s proof is covered in any trignometry book you can refer it
Please explain me i dont have time,Can i ask another which is not related with trigonometry and we can do this later?
i`ll give you some proof intuitively |dw:1361984238640:dw| pi/2 + pi = 3pi/2 so it`s again zero at 3pi/2 and 3pi/2 + pi = 5pi/2 and so on...
Join our real-time social learning platform and learn together with your friends!