Question

13 P 0

Answer 1

@campbell_st

Answer 2

its a proportion

Answer 3

well its a straight up calculator question...

do you have a calculator that does permutations...?

Answer 4

i dont....

Answer 5

ok... so here is the formula

\[^{n}P_{k} = \frac{n!}{(n - k)!}\]

so in your question

n = 13 and k = 0

so you have

\[^{13}P_{0} = \frac{13!}{(13 - 0)!} = 1\]

hope this helps.

Answer 6

so if you have 13 C 12, how do you set that up?

Answer 7

factorial notation is

\[n! = 1 \times 2 \times 3 \times 4\times 5 \times.... \times n\]

so as an example

\[3! = 1 \times 2 \times 3 = 6\]

\[4! = 1 \times 2 \times 3 \times 4 = 24\]

\[5! = 1 \times 2\times 3 \times 4 \times 5 = 60\]

Answer 8

so in my equation is n! = 13

Answer 9

or do you multiply 13 * 12 and then find the divisibility?

Answer 10

ok... so this is a combination

the combination formula is slightly different.

\[^{n}C_{r} = \frac{n!}{r!(n - r)!} \]

in your question you have

\[^{13}C_{12} = \frac{ 13!}{12!(13-12)!} = 13\]

Answer 11

OH!!!! i get it now

Answer 12

glad to help