Question

Find the General solution of secx+tanx=0
.
.
ANSWER={}

Answer 1

huh????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????

Answer 2

Hey ... the way would be...
Simplify secx and tanx in terms of sinx and cosx...
secx = 1/cosx and tanx = sinx/cosx

Answer 3

O.O !! what happened ??

Answer 4

i got the answer but its not coming a null set

Answer 5

secx/tanx=-1

Answer 6

Show your work...

Answer 7

1/cosx * cosx/sinx

Answer 8

1/sinx

Answer 9

1/sinx=-1 <<--what to do after this

Answer 10

Hey the problem is in the first step itself... You are dividing by tanx but not making sure that you can divide only when tanx is not equal to 0... Else you would be dividing by 0 which is itself NOT PERMITTED...

Answer 11

so how to start?

Answer 12

In your case also, 1/cosx * cosx/sinx = 1/sinx only when cosx is not equal to 0...
Which gives sinx = -1 with cosx neq 0
i.e., x= (4n-1) pi/2 with x neq (2n+1)pi/2

Answer 13

That means from first case, x is some multiple of pi/2
from second case, x can't be a multiple of pi/2
Hence giving no possible solution ...
@koli123able *neq* means not equal to...

Answer 14

Hey you clear ??? @koli123able ... Respond...

Answer 15

yup

Answer 16

Okay then... pleasure helping...