Quick one! If I invert the inverse (A-AX)^-1

so ((A-AX)^-1)^-1

Do I just cancel the inverse signs and get A-AX, or do I need to rearrange the terms, because for example, the inverse of AB is B^-1 * A^-1

Question

Quick one! If I invert the inverse (A-AX)^-1

 so ((A-AX)^-1)^-1

Do I just cancel the inverse signs and get A-AX, or do I need to rearrange the terms, because for example, the inverse of AB is B^-1 * A^-1

anonymous · Answer

$$((A-AX)^{-1})^{-1}$$ = ?

anonymous · Answer

Anyone good with matrices know this? I have a feeling it might not be as simple as "cancelling" the inverse signs.

anonymous · Answer

I think you are making it to complicated for the meaning of the question. Although I agree with your analysis.. the question probably just wants you to know the inverse of an inverse is the original.

anonymous · Answer

Thats what Im not sure of.  Because the inverse of AB is not A^-1 * B^-1 , the order is switched, so its actually B^-1 A^-1

anonymous · Answer

arg, nevermind, apparent the inverse of an inverse is just the original. You were right, I overcomplicated this.

anonymous · Answer

I have overcomplicated plenty of questions. Thanks;)