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Solve the following logarithmic equation.In (x+5) + In (x-2) = 2 In x. Simplofy your answer. Type an integer or a fraction. Use a comma to separate answers as needed.
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you know how the log addition works right?
use ln(a) +ln(b) = ln(ab)
and that ln(x) is defined only on x>0
x=10/3. Do I need to detail the solution?
Ok, \[\ln (x-5) + \ln(x+2)=\ln(x^2)\] then\[\ln(x-5) +\ln (x+2)-\ln(x^2)=0\] \[\ln(((x-5)*(x+2))/(x^2))=0\] \[x^2+3x-10=e^0*x^2\] \[3x=10\] Finally\[x=10/3\]
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