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Chemistry 16 Online
OpenStudy (anonymous):

how many grams of oxygen gas will be required to react completely with 92.0 grams of solid sodium to form solid sodium oxide?

OpenStudy (abb0t):

First start by writing a balanced chemical equation between sodium (Na) and oxide (O-)

OpenStudy (abb0t):

Can you do that?

OpenStudy (anonymous):

I'm typing an answer for you :)

OpenStudy (anonymous):

sorry the site locked up.....

OpenStudy (anonymous):

Start by writing a balanced equation. Then you can take 92g Sodium x 1 mol sodium/molar mass of sodium(that leaves you with moles of Sodium). Then multiply that by x mol Oxygen/x mol sodium (this gives you moles of Oxygen). Then multiply that by molar mass/1 mol Oxygen(This leaves you with the amount in grams you need to react with sodium)

OpenStudy (anonymous):

I have the balanced equation done. i am on the factor labeling part.

OpenStudy (anonymous):

what is your balanced equation? .. I can work out the math so you have something to check it to

OpenStudy (anonymous):

Thank you so much!

OpenStudy (anonymous):

You are very welcome

OpenStudy (anonymous):

the balanced equation that I have is 4Na + O2 --> 2Na2O

OpenStudy (anonymous):

I got 128g O2

OpenStudy (anonymous):

Okay that's what I wrote, but that's one spot I'm weak in. Lol... I came up with 32.0139191 or 32.01g... Let me try

OpenStudy (anonymous):

your set up should look like this... 92g Na x 1 mol Na/22.99g Na x 1 mol O2 / 4 mol Na x 32g O2/1 mol O2 = 32.01 when you type it in it should be (92x32) / (22.99x4)

OpenStudy (anonymous):

yes, thank you! I forgot to put it over 4 mol Na. Ooops! hahah. But when you find the molar mass of Na2O, would it be 61.98 or do you have to use it from the equation where its 2Na2O?

OpenStudy (anonymous):

Just the mass of Na2O :)

OpenStudy (anonymous):

Okaay, that's what I thought. Hahah. Thank you!

OpenStudy (anonymous):

No prob. Glad I could help you out.

OpenStudy (anonymous):

Could I ask you about one more problem? hahah.

OpenStudy (anonymous):

I can sure try. Lol. but may not know the answer. :)

OpenStudy (anonymous):

It says: Calculate the # of grams of Na2O that will be produced when 5.00 moles of solid sodium react with oxygen gas. This is how I have it set up: 5.00ol Na x 22.99 g Na/1 mol Na x 4 mol Na/2 mol Na x 1 mol Na2O/61.98 g Na2O Is that right? Haha

OpenStudy (anonymous):

No. You don't need to convert Na to grams ... so just 5 mol Na x 2 mol Na2O/4 mol Na x 61.98 g/1 mol Na2O = 154.95g

OpenStudy (anonymous):

Ohhh, alrighty! I see, becuase then the grams of Na wouldn't cancel out! I understand!

OpenStudy (anonymous):

Exactly. :) You made it more complicated than it has to be. lol!! Good luck

OpenStudy (anonymous):

Hahah. Yes, I did! lol. Thank you!

OpenStudy (anonymous):

Is that all?

OpenStudy (anonymous):

Yes m'am! :)

OpenStudy (anonymous):

Ok. Good luck in you're studies. If you have questions you can email me cntrywrtr@yahoo.com and I will try to help you. My name is Chrystal.

OpenStudy (anonymous):

Awesome, Thank you so much!

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