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In how many ways can a committee of five men and four women be formed from a group of nine men and nine women?
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\[\dbinom{9}{5}\times \dbinom{9}{4}\] do you know how to compute these numbers?
im using permutations and combinations though
is that still the right answer?
it is 9 choose 5 times 9 choose 4
maybe you have seen \[\dbinom{9}{5}\] written as \[_9C_5\] it is the same thing
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soo on the calculator would it be 9 C 5
oh! okay sweet
yes
and in fact 9 choose 5 is the same number as 9 choose 4
okay and then when you get the two seperate answers do you divide?
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oh no you multiply!
ohh! okay
you get \[\dbinom{9}{5}=\dbinom{9}{4}=126\] so your answer is \[126\times 126=126^2\]
thank you!
yw
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