Question

Find the equation of the tangent line to x^2+2y^2=3

Answer 1

tangent where?

Answer 2

To the equation above

Answer 3

it has to be tangent at some point, if you want to get the equation of the tangent line

Answer 4

I have dy/dx as being -2x/74

Answer 5

oh yeah at points (1,1) missed that part

Answer 6

-2x/4y (fat fingers)

Answer 7

\[ x^2+2y^2=3
\]
\[2x+4yy'=0\]
\[y'=-\frac{x}{2y}\]

Answer 8

Right, i am that far. So I should be able to plug m (x,y) into y' to get my slope, then use point slope form to get my tang line right?

Answer 9

replace \(x\) and \(y\) by 1 to get the slope, which is \(-\frac{1}{2}\)
now use the point slope formula with
\[m=-\frac{1}{2}, x_1=y_1=1\]

Answer 10

yeah, so the second part of the question is when I am checking myself, the tang line should be on the edge of the elpise right? Because the line i made passes through the elipse and not on the edge