find the Differential Equation of the given Family.

Y= Ce^(2x) + e^(-2x)

Question

find the Differential Equation of the given Family.

Y= Ce^(2x) + e^(-2x)

abb0t · Answer

Take the first and second derivative of the given solution.

abb0t · Answer

Then do a little substitution of y...

anonymous · Answer

@mathlife You should really follow abb0t's advice. Do not expect us to give a solution for you.

anonymous · Answer

If it worked out, close the question. If you are still having trouble, let us know.

turingtest · Answer

there is a neat way to do it with matrices :)

abb0t · Answer

I don't think they should expect ANY answers for any math course above Calculus 1.

abb0t · Answer

@TuringTest HAHAHA i prefer to stay away from that route. Nope. No way.

turingtest · Answer

aw, but it's really pretty cool and fast, plus it works for any set of exponents e^ax, e^bx

anonymous · Answer

@TuringTest No need to make things more complicated... you may have to end up explaining matrix operations to OP.

abb0t · Answer

Can't you use Wronskian too?

turingtest · Answer

Don't worry, I wasn't going to post, you abb0t has described enough
no, much easier than the wronskian

turingtest · Answer

no, because you don't get a square matrix

anonymous · Answer

BTW guys I think @mathlife is leaving out some info - I can think of a first-order DE that satisfies this as well as the double-root second-order linear DE we're all thinking of...