Question

How would you start this problem?
sqrt3sinx+cosx=1

Answer 1

Ok I did that and I got 3sin^2x+cos^2=1. Then what?

Answer 2

or you can divide by 2 on both sides...

Answer 3

ohh.. i thought the question was
\(\sqrt3 \sin x+\cos x=1\)

Answer 4

it is

Answer 5

then you need to divide by 2 on both sides....

Answer 6

and use the identity
sin A cos B +cos A sin B =.... ?

Answer 7

where is the 2 coming from?

Answer 8

you have sqrt 3
but for standard angle, sin or cos value is sqrt 3/2
hence , divide by 2

Answer 9

I was thinking of using the transformation: \(2\cdot\sin\left(\dfrac{\pi}{6} + x\right) = 1\).

I like hartnn's solution better, but unique answers don't care how you find them.

Answer 10

i'll get same thing....

Answer 11

doubts ?
should i give next step ?

Answer 12

once you divide by 2 what do you get. I am having a hard time figuring out what that looks like?