Question

Are my answers correct? :)

Answer 1

i know the answer to ur question if i tell u u going to have to fan meh?

Answer 2

how did you figure hose out ?

Answer 3

did you use this :
If a, b and c are the lengths of the sides of a triangle and c is the largest side, then
(1) a^2 + b^2 = c^2 => right triangle
(2) a^2 + b^2 > c^2 => acute-angled
(3) a^2 + b^2 < c^2 => obtuse-angled
?

Answer 4

its easy

Answer 5

im doing same stuff

Answer 6

so they aren't correct? i dont know how to figure it out

Answer 7

you can use this :
If a, b and c are the lengths of the sides of a triangle and c is the largest side, then
(1) a^2 + b^2 = c^2 => right triangle
(2) a^2 + b^2 > c^2 => acute-angled
(3) a^2 + b^2 < c^2 => obtuse-angled

first figure out which is largest side, c

Answer 8

so the first one is still obtuse?

Answer 9

lets check!
largest side = c =12 , c^2 =12^2 =144
a^2+b^2 = 9^2 +10^2 = 81+100 =181
181 > 144
so, a^2+b^2 > c^2
so , according to "(2) a^2 + b^2 > c^2 => acute-angled"
this triangle is acute triangle.
did you get this ?
can you do similar thing for others ?

Answer 10

OOHHH i get it. Thankyou :)

Answer 11

welcome ^_^
you can ask if you wanna verify others too....

Answer 12

the second one is obtuse?

Answer 13

i did 17*17 + 15 + 8

Answer 14

the sides were, 8,15,17 right ?
largest side = c = 17, c^2 =....?
a^2+b^2 = 8^2+15^2 =.... ?

Answer 15

1185?

Answer 16

which calculator are you using ? :P
c^2 = 17^2 =289
a^2+b^2 = 8^2+15^2 =64 +225 = 289
so which case ?

Answer 17

when both are equal ?

Answer 18

they're right triangles

Answer 19

yes, 2nd one is right triangle, what about 3rd ?

Answer 20

acute?

Answer 21

what were the sides of 3rd triangle ?

Answer 22

5 6 and 10

Answer 23

largest side = c =10, c^2 =10^2 =...
a^2+b^2 = 5^2+6^2 =... ?

Answer 24

61?

Answer 25

yes, so is 61 > 100 or 61 < 100 ?

Answer 26

less than. so its obtuse?

Answer 27

yes.