Question

Need The Full Steps On How To Combine Like Terms and Simplify This Problem:
4/5(2z+10)-1/2(z+3)

Answer 1

multiply it out to obtain 8/5z + 8 -1/2z - 3/2

then add terms with z and constants together

Answer 2

how do i show the work to get 8/5z+8-1/2z-3/2

Answer 3

is the question

1. \[\frac{4}{5} (2z + 10) - \frac{1}{2}(z + 3)\]



or is it

2. \[\frac{4}{5(2z + 10)} - \frac{1}{2(z + 3)}\]

Answer 4

the 1st one campbell

Answer 5

4/5 * 2z = 8/5z ...etc

Answer 6

ok... so you are adding and subtracting fractions

\[( \frac{8}{5} - \frac{1}{2})z + (8 - \frac{3}{2}) \]

now just simplify for the answer.

Answer 7

Campbell how do i show work to show that i got 8/5

Answer 8

well it

\[\frac{4}{5} \times 2 = \frac{8}{5} \]

you are distributing

Answer 9

Now whaT

Answer 10

Campbell

Answer 11

ok... so the same for the 10

\[\frac{4}{5} \times 10 = 8\]

next look at the 2nd set of brackets

\[-\frac{1}{2} \times 1 = \frac{1}{2} z\]

and

\[- \frac{1}{2} \times 3 =- \frac{3}{2}\]

Answer 12

I'm So Confused I Suck At Math Like Big Time

Answer 13

ok... here are the bits again

distributing means multiplying the outside by everything inside.

\[\frac{4}{5} \times 2z = \frac{8}{5} z\]

\[\frac{4}{5} \times 10 = 8\]

\[-\frac{1}{2} \times z =- \frac{1}{2} z\]

\[- \frac{1}{2} \times 3 = \frac{3}{2}\]

so after distributing you get

\[\frac{8}{5} z + 8 - \frac{1}{2} z - \frac{3}{2} \]

like terms have the same letter and can be added or subtracted

then you will get

\[(\frac{8}{5} - \frac{1}{2})z + ( 8 - \frac{3}{2}) \]

put the fractions over the same denominators will give

\[(\frac{16}{10} - \frac{5}{10}) z + ( \frac{16}{2} - \frac{3}{2})\]

this simplifes to

\[\frac{11}{10} z + \frac{13}{2} \]

change the improper fractions to mixed numbers..

\[1 \frac{1}{10} z + 6 \frac{1}{2} \]