Question

Evaluate the limit of an infinity

Answer 1

@mathcalculus Hi :)
\(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\)
did you have trouble posting the limit function ?
because we can't see the question entirely.

Answer 2

lim x->inifinity 5x+7/3x^2-7x+5

Answer 3

good, in limits tending to infinity, we generally divide numerator and denominator by the highest power of 'x' , here divide numerator and denominator by x^2, what u get ?

Answer 4

i dont understand..

Answer 5

because its the highest power of 'x'
we actually use the fact that since x-> infinity, 1/x =0
or any power of x in denominator , like 1/x^n also =0

Answer 6

awesome thank you

Answer 7

just to verify, what answer did you get for this ?

Answer 8

0

Answer 9

yes :)

Answer 10

how about this problem: 7x^3-7x^2-2x/3-6x-4x^3

Answer 11

what will you divide ?

Answer 12

same lim-> infinity

Answer 13

the highest 'x' ........ x^3?

Answer 14

yup, then what u get ?

Answer 15

7/-4 :)

Answer 16

\(\huge \color{red}{\checkmark}\)

Answer 17

is it different for horizontal limits?

Answer 18

for example:
Find the horizontal limit(s) of the following function:
f(x) 7x^3-5x^2-10x/3-8x-7x3

Answer 19

its same for horizontal limits also.....

Answer 20

7/(-7)=-1

Answer 21

i misread the the question. It does not say the limit to infinity

Answer 22

It only says:
Find the horizontal limit(s) of the following function:
f(x) 7x^3-5x^2-10x/3-8x-7x3

Answer 23

horizontal limits means we have to take x->infinity

Answer 24

weird.... i'm not getting the answer correct :/

Answer 25

let me go through horizontal limits again....

Answer 26

its correct, for hori. limits, we evaluate lim x-> infinity of f(x)
and i still get -1 for that.

Answer 27

\(f(x)=[7x^3-5x^2-10x]/[3-8x-7x^3]\)
right ?

Answer 28

?

Answer 29

try 1 and -1 ...

Answer 30

wrong again

Answer 31

actually, i think we need to find limit at x-> -infinity also

Answer 32

how?

Answer 33

put x=-y
so, when x->-infinity, y->infinity.
but then i still get bot limit as -1 ...

Answer 34

nvm

Answer 35

thanks again

Answer 36

ok...welcome.

Answer 37

are you a student or have teaching backgrounds in cal?

Answer 38

i studied calculus few years ago...i don't teach, but i come here to help in my free time :)

Answer 39

Oh great because we actually did get the answer right. Only they wanted the answer written twice. (don't ask, it's just weird lol)

Answer 40

lol :P ok, glad that we got it right :)

Answer 41

well i can use a little help with this one..

Answer 42

find the points (x0 , f(x0))
and (x1, f(x1))
then do u know how to find slope given 2 points ?

Answer 43

i thought i did. i got the points: (2,28) and (3,37)

Answer 44

but the slope isn't right.....

Answer 45

i got m=9

Answer 46

isn't that -28 ? instead of 28 ?

Answer 47

for x=3, -45-8 = -52

Answer 48

*-53

Answer 49

yeah i forgot to type the sign in just now

Answer 50

so, points are :
(2,-28) and (3,-53)
right ?
slope =..?

Answer 51

-25

Answer 52

yes, its correct.

Answer 53

:)

Answer 54

Let f(x) be the function 8x^2-3x+11 . Then the quotient f(2+h) - f(2)/h
can be simplified to ah+b for:

a=

b=

Answer 55

next time, make new post for new question...

Answer 56

its my first time using this website.

Answer 57

cool, i'm getting the hang of it.

Answer 58

ask me if you have any doubts browsing this site...

Answer 59

the quotient f(2+h) - f(2)/h is just the derivaive at x=2

Answer 60

Im not exactly sure with derivatives

Answer 61

okk...continue on that new post....