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OpenStudy (anonymous):
Balance the following redox reactions
1. P4+OH- -->PH3+HP02-
2.Cl2O7+H2O2 -->ClO2- + O2+ H+
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OpenStudy (chmvijay):
. P4+6OH- --> PH3+3HP02-
OpenStudy (anonymous):
@chmvijay Here I got the oxidation no of P in PH3 as -3 and that of p in HPO2- as1.Then which one should i consider as oxidation?
OpenStudy (anonymous):
Can you explain the steps?
OpenStudy (anonymous):
The question is to be answered either through ion exchange method or oxidation no method.
OpenStudy (chmvijay):
HPO2- how do calculated the oxidation sate to be +1 its +3 i think
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OpenStudy (anonymous):
yes. sorry its +3
.
OpenStudy (anonymous):
then what about my doubt ?
OpenStudy (chmvijay):
what doubt
OpenStudy (anonymous):
can you explain the steps to balance it?
OpenStudy (chmvijay):
wt is toal negative charge on left side
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OpenStudy (anonymous):
i mean the steps to balance the equation?
OpenStudy (chmvijay):
6OH_ mean total charge is -6 since P4 is neutral charge is zero
hence total charge on left hand side of eqn is -6
OpenStudy (chmvijay):
we should chose in such way that right hand side also the charge should be -6
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