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Chemistry 15 Online
OpenStudy (anonymous):

Balance the following redox reactions 1. P4+OH- -->PH3+HP02- 2.Cl2O7+H2O2 -->ClO2- + O2+ H+

OpenStudy (chmvijay):

. P4+6OH- --> PH3+3HP02-

OpenStudy (anonymous):

@chmvijay Here I got the oxidation no of P in PH3 as -3 and that of p in HPO2- as1.Then which one should i consider as oxidation?

OpenStudy (anonymous):

Can you explain the steps?

OpenStudy (anonymous):

The question is to be answered either through ion exchange method or oxidation no method.

OpenStudy (chmvijay):

HPO2- how do calculated the oxidation sate to be +1 its +3 i think

OpenStudy (anonymous):

yes. sorry its +3 .

OpenStudy (anonymous):

then what about my doubt ?

OpenStudy (chmvijay):

what doubt

OpenStudy (anonymous):

can you explain the steps to balance it?

OpenStudy (chmvijay):

wt is toal negative charge on left side

OpenStudy (anonymous):

i mean the steps to balance the equation?

OpenStudy (chmvijay):

6OH_ mean total charge is -6 since P4 is neutral charge is zero hence total charge on left hand side of eqn is -6

OpenStudy (chmvijay):

we should chose in such way that right hand side also the charge should be -6

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