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Mathematics 16 Online
OpenStudy (anonymous):

can someone show me how to get from y=sec^2x-tan^2x to y=(tan^2x+1)-tan^2x ?

OpenStudy (anonymous):

\[y=\sec ^{2}x-\tan ^{2}x\] to \[y=(\tan^{2}x+1)-\tan^{2}x\]

hartnn (hartnn):

sec^2x = 1+ tan^2x is a standard identity

OpenStudy (anonymous):

oh duh... sigh.

hartnn (hartnn):

you need to remember it

OpenStudy (anonymous):

thanks, writing it down now :) - again

hartnn (hartnn):

other 2 are : cosec^2x = 1+cot^2x sin^2x+cos^2x = 1

OpenStudy (anonymous):

cosec is csc?

hartnn (hartnn):

yes

OpenStudy (anonymous):

wow these identities save LOTS of time

hartnn (hartnn):

and solve lots of problems :)

OpenStudy (anonymous):

again, thanks

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