Question

Solve the system of linear equations by substitution
y = 5x + 6
y = -2x - 8

Answer 1

cant explain it but i can give you an example:
equation 1: 14x+2y=20
equation 2: 5x-y=8
First step is to get on of the varibles to cancel out so leave the first eqation alone put change the second in this problem so:
5x-y=8 becomes 2(5x-y=8) which equals 10x-2y=16
the next step is to subtract them like this:
14x+2y=20
10x-2y=16
the +2y and the -2y cancel out so the answer then would be
4x=4 which means 1=x
then you plug the answer 1 in for x into on of the equations to find y so:
5(1)-y=8 = 5-y=8 =-y=3 =y=-3
so the system answer is (1,-3)

Answer 2

i just gave you an example

Answer 3

-5x-6 = 5 Add 5 6 to both sides.
-5x = 11 Divide both sides by -5
x = -11/5 Now substitute this for x into either of the two original equations and solve for y. Let's use the second equation:
y-5x = 3 Substitute x = -11/5
y-5(-11/5) = 3 Simplify.
y+11 = 3 Subtract 11 from both sides.
y = - 8
The solution is: (-11/5, -8) Let's check the graph of the two lines represented by the two equations.
The solution will be seen as the point of intersection of the two lines.

Answer 4

Which set of data has 3 modes?

33, 34, 31, 34, 39, 35, 37, 31, 39, 30

31, 34, 31, 34, 39, 35, 37, 31, 34, 35

32, 35, 31, 36, 41, 40, 37, 30, 42, 29

32, 35, 36, 35, 32, 36, 32, 36, 35, 32