Question

ln (t-1)2 = 3

Answer 1

use the log law for powers to simplify it

\[2 \ln(t - 1) = 3\]

now divide both sides by 2

\[\ln (t - 1) = \frac{3}{2}\]

now raise both sides as powers of e

this uses the log law

\[a^{\log_{a}(x)} = x\]

so

\[e^{\ln(t -1)} = e^{\frac{3}{2}} \]

then

\[t - 1 = e^{\frac{3}{2}}\]

I'll let you finish solving for t