Question

Complex conjugate anyone?

x-4j^2+3j=yj+2x(-j)

Answer 1

\[\Large x-4(j)^2+3j=yj+2x(-j) \]

Like that?

Answer 2

I figured it out. It follows:
\[x-4j^2+3j=yj+2xj^3\]
\[x-4(-1)+3j=yj+2x(-j)\]
\[(x+4)+3j=yj+2x(-j)\]
\[(x+4)+3j=0+(y+2x)(-j)\]
\[(x+4)+3j=0+(y-2x)j\]
formula \[a+bj=c+dj\]

X ends up being -4 so that it equals 0 and y end up being -5 so the quantitiy (y-2x) equals 3. You're welcome.