Let R be the region bounded by the graphs of y=cos((pi x)/2) and y=x^2-(26/5)x+1.

Find the area of R.
http://goo.gl/vSltp

Question

Let R be the region bounded by the graphs of y=cos((pi x)/2) and y=x^2-(26/5)x+1. 

Find the area of R.
http://goo.gl/vSltp

anonymous · Answer

I really just need confirmation that what I have is right. (hopefully it is anyway)

anonymous · Answer

$$\int\limits_{0}^{5}(\cos(\pi x/2)-(x^2 - (26/5) x +1))dx=55/3 + 2/\pi = 18.97 $$

anonymous · Answer

Does this make sense?  I'm a little unsure.

anonymous · Answer

@phi

phi · Answer

It is the correct setup, but I did not check your integration

anonymous · Answer

As long as it's the correct setup then I'm glad for the reassurance. ;)

phi · Answer

top curve - lower curve gives a height
height*dx gives an area
integrate along x to get the total area.