Question

What is a possible quantum number set for an electron in the 2s orbital of a beryllium (Be) atom?

(2, 0, 0, -½)

(2, 0, 1, -½)

(2, 1, 0, -½)

(2, 1, 1, +½)

Answer 1

@jhonyy9

Answer 2

@mathslover

Answer 3

I think (2, 0, 0, -1/2)

As s orbital 2s, n must = 2 and l = 0

m can equal between -l and +l, therefore zero too

Answer 4

Okay, thank you!

Answer 5

That may very well be wrong.

Answer 6

Oh :( this question confuses me

Answer 7

yes it can be (2,0,0, \(\pm \frac{1}{2} \)

first option is right

Answer 8

got it @sarahc ?

Answer 9

thank you!!!!

Answer 10

Also welcome to OpenStudy @sarahc . Best of luck for your journey here in OS

Answer 11

thank ya :) & I'm grateful for the help!

Answer 12

Welcome Sarah

Answer 13

Which of the following quantum number combinations is not allowed in a ground-state atom?

(2, 1, 1, -½)

(8, 7, -7, +½)

(5, 5, -5, +½)

(1, 0, 0, +½)

Answer 14

@mathslover another question? :)

Answer 15

o.O sorry sarah, my laptop battery is getting low

Answer 16

Though, I think C.) (5, 5, -5, +½) is the correct answer. but please try to attempt it yourself

Answer 17

bbye

Answer 18

I thought it was c as well. thanks :)