Question

Find the x -intercept and y -intercept of f(x) = (x - 4)^2(x+5)^2

Answer 1

To get x-intercept put y=0 in the equation f(x) = (x - 4)^2(x+5)^2=y
to get y-intercept put x=0 in the equation f(x) = (x - 4)^2(x+5)^2=y

Answer 2

ok doing it atm

Answer 3

first equation so far is 2x^3 +x^4 - 39x^2 - 40x + 400 = 0 Do I follow the correct path...?

Answer 4

sorry to say no :P

Answer 5

(x - 4)^2(x+5)^2=0
can't you directly say, x=4,4,5,5
like if (x-a)=0, x=a
(x-a)(x-b)=0, then x=a,b
(x-a)^2=0, then x=a,a

Answer 6

x= -4 , 4, -5, 5 ??

Answer 7

sorry, it'll be,
(x - 4)^2(x+5)^2=0
x=4,4,-5,-5
why -4 and 5 ??

Answer 8

I mean why did you type 4 and 5 2 times

Answer 9

(x - 4)^2(x+5)^2=0
(x-4)^2 = 0 , (x-5)^2=0,
(x-4)=0 , (x-4)=0 , (x-5) =0, (x-5)=0
ok, (x-a)^2=0 is a Quadratic Equation and it MUST have 2 roots.
in this case, (x-a)^2=0, have 2 SAME(equal) roots as 'a'
so we can say that its ha only 1 root 'a' but more precisely, it has 2 equal roots, a,a

Answer 10

for the intercept case, x-intercept = 4,4 implies that the curve f(x) cuts the point (4,0) TWICE.

Answer 11

I see

Answer 12

doubts ?

Answer 13

and whats y-intercept=... ?

Answer 14

4 4 -5 -5 400 :P

Answer 15

\(\huge \color{green}\checkmark\)