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Mathematics 7 Online
OpenStudy (anonymous):

Rewrite with only sin x and cos x. cos 2x - sin x

OpenStudy (anonymous):

is it cos2x - sin2x - sin x ?

OpenStudy (anonymous):

Use the double angle formula: Cos(2x) = cos^2 x - sin^2 x It's a trig identity, so you just have to memorize it. Here's a helpful website: http://www.sosmath.com/trig/Trig5/trig5/trig5.html

OpenStudy (anonymous):

Does that help?

OpenStudy (anonymous):

@Nanoman Ah, so I would have cos^2x - sin^2x - sin x?

OpenStudy (anonymous):

Yes, but keep track of your notation. It looks like you're saying cos^(2x) -sin^(2x). I should have said cos^2 (x) -sin^2 (x) so you wouldn't be confused.

OpenStudy (anonymous):

Ok I understand that. And that would be my final answer correct?

OpenStudy (anonymous):

You can also simplify the term "cos^2 (x) -sin^2 (x)" as shown on the site, but I don't think you'll need to. You want it in terms of cos(x), so this would be correct. Just to be safe, you can convert cos^2 (x) to (cosx)^2. The two are equivalent, and you can do the same thing with any trig function.

OpenStudy (anonymous):

@Nanoman perfect thanks a lot:)

OpenStudy (anonymous):

No problem!

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