Question

What is the object's position at t = 6s?
I think it should be 360m, but it's not an option.

A)10m
B)180m
C)60m
D)3600m

Answer 1

The distance travelled is the area under the velocity-time graph

Answer 2

the answer is 180m

Answer 3

@Xavier is correct. Just calculate the area under the curve...and notice it's a triangle.

Answer 4

\[\tan \theta=a=\frac{ v }{ t }=10\frac{ m }{ s ^{2} }\]
\[s=ut + \frac{ 1 }{ 2 }at ^{2}\]
=0+180